8k^2+49k-49=0

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Solution for 8k^2+49k-49=0 equation: 



8k^2+49k-49=0

a = 8; b = 49; c = -49;
Δ = b2-4ac
Δ = 492-4·8·(-49)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-63}{2*8}=\frac{-112}{16}
=-7
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+63}{2*8}=\frac{14}{16}
=7/8
$

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